3sum-closest

Given an array nums of n integers and an integer target, find three integers in nums such that the sum is closest to target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

Example:

Given array nums = [-1, 2, 1, -4], and target = 1.

The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

My code:
import numpy as np
class Solution:
    def threeSumClosest(self, nums, target):
        """
        :type nums: List[int]
        :type target: int
        :rtype: int
        """
        #First Sort
        index=np.argsort(nums)
        close_value=100000000000
    
        for i in range(len(nums)):
            value1=nums[index[i]]
            lstart=i+1
            rstart=len(nums)-1
            while lstart<rstart:
                #print('running lstart %d rstart %d'%(lstart,rstart))
                value2=nums[index[lstart]]
                value3=nums[index[rstart]]
                if abs(value1+value2+value3-target)<close_value:
                    close_value=abs(value1+value2+value3-target)
                    record=[]
                    record.append(value1)
                    record.append(value2)
                    record.append(value3)
                   
                if value1+value2+value3<target:
                    lstart+=1
                else:
                    rstart-=1
        return sum(record)
                    
        
Solution:
https://leetcode.com/problems/3sum-closest/