Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between).
For example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its zigzag level order traversal as:
[
[3],
[20,9],
[15,7]
]
My code:
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def zigzagLevelOrder(self, root):
"""
:type root: TreeNode
:rtype: List[List[int]]
"""
if root==None:
return []
search_list=[root]
read_label=True
record_list=[]
while search_list:
tmp_record=[]
will_search=[]
for item in search_list:
left=item.left
if left!=None:
will_search.append(left)
right=item.right
if right!=None:
will_search.append(right)
tmp_record.append(item.val)
if not read_label:
tmp_record.reverse()
search_list=will_search
record_list.append(tmp_record)
read_label=not read_label
return record_list
Solution: https://leetcode.com/problems/binary-tree-zigzag-level-order-traversal/submissions/