You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
Example 1:
Input: 2 Output: 2 Explanation: There are two ways to climb to the top.
- 1 step + 1 step
- 2 steps Example 2:
Input: 3 Output: 3 Explanation: There are three ways to climb to the top.
- 1 step + 1 step + 1 step
- 1 step + 2 steps
- 2 steps + 1 step
My code:
import numpy as np
class Solution:
def climbStairs(self, n):
"""
:type n: int
:rtype: int
"""
if n==0:
return 1
self.matrix=np.zeros(n)-1
count=self.Sub_climb(n)
return int(count)
def Sub_climb(self,n):
if n==1:
return 1
if n==2:
return 2
if self.matrix[n-1]!=-1:
return self.matrix[n-1]
count1=self.Sub_climb(n-1)
count2=self.Sub_climb(n-2)
self.matrix[n-1]=count1+count2
return self.matrix[n-1]