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There are a total of n courses you have to take, labeled from 0 to n-1.

Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1]

Given the total number of courses and a list of prerequisite pairs, is it possible for you to finish all courses?

Example 1:

Input: 2, [[1,0]] 
Output: true
Explanation: There are a total of 2 courses to take. 
             To take course 1 you should have finished course 0. So it is possible.
Example 2:

Input: 2, [[1,0],[0,1]]
Output: false
Explanation: There are a total of 2 courses to take. 
             To take course 1 you should have finished course 0, and to take course 0 you should
             also have finished course 1. So it is impossible.
Note:

The input prerequisites is a graph represented by a list of edges, not adjacency matrices. Read more about how a graph is represented.
You may assume that there are no duplicate edges in the input prerequisites.

from collections import defaultdict
class Solution(object):
    def canFinish(self, numCourses, prerequisites):
        """
        :type numCourses: int
        :type prerequisites: List[List[int]]
        :rtype: bool
        """
        record_dict=defaultdict(list)
        for item in prerequisites:
            key1=item[0]
            require=item[1]
            record_dict[key1].append(require)
        
        cid=[0]*numCourses
            
        for i in range(numCourses):            
            if not self.dfs(record_dict, i, cid):
                return False
    
        return True
        
    def dfs(self, graph, i, visited):
        if visited[i] == 1:
            return False
        elif visited[i] == 2:
            return True
        visited[i] = 1
    
        for j in graph[i]:
            if not self.dfs(graph, j, visited):
                return False
        
        visited[i] = 2
    
        return True
    
               

Solution: https://leetcode.com/problems/course-schedule/