Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.
(i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]).
Find the minimum element.
You may assume no duplicate exists in the array.
Example 1:
Input: [3,4,5,1,2]
Output: 1
Example 2:
Input: [4,5,6,7,0,1,2]
Output: 0
My code:
class Solution(object):
def findMin(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
if len(nums)==1:
return nums[0]
left=0
right=len(nums)-1
if nums[right]>nums[left]:
return nums[0]
while right>=left:
mid=left+(right-left)/2
if nums[mid]>nums[mid+1]:
return nums[mid+1]
if nums[mid-1]>nums[mid]:
return nums[mid]
if nums[mid]>nums[0]:
left=mid+1
else:
right=mid-1
Solution: https://leetcode.com/problems/find-minimum-in-rotated-sorted-array/