Given two integers representing the numerator and denominator of a fraction, return the fraction in string format.
If the fractional part is repeating, enclose the repeating part in parentheses.
Example 1:
Input: numerator = 1, denominator = 2
Output: "0.5"
Example 2:
Input: numerator = 2, denominator = 1
Output: "2"
Example 3:
Input: numerator = 2, denominator = 3
Output: "0.(6)"
My code:
class Solution(object):
def fractionToDecimal(self, numerator, denominator):
"""
:type numerator: int
:type denominator: int
:rtype: str
"""
n, remainder = divmod(abs(numerator), abs(denominator))
sign = '-' if numerator*denominator < 0 else ''
result = [sign+str(n), '.']
stack = []
while remainder not in stack:
stack.append(remainder)
n, remainder = divmod(remainder*10, abs(denominator))
result.append(str(n))
idx = stack.index(remainder)
print(idx)
result.insert(idx+2, '(')
result.append(')')
print(result)
return ''.join(result).replace('(0)', '').rstrip('.')Solution: https://leetcode.com/problems/fraction-to-recurring-decimal/