Length of Last Word.md

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

Example:

Input: "Hello World" Output: 5

class Solution:
    def lengthOfLastWord(self, s):
        """
        :type s: str
        :rtype: int
        """
        if len(s)==0:
            return 0
        length=len(s)
        count=0
        marked=False
        for i in range(len(s)):
            if s[i]==' ':
                marked=True
                continue
            if s[i]!=' ' and marked:
                marked=False
                count=0
            count+=1
        return count

Solution: https://leetcode.com/problems/length-of-last-word/