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Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3]....

Example 1:

Input: nums = [1, 5, 1, 1, 6, 4]
Output: One possible answer is [1, 4, 1, 5, 1, 6].
Example 2:

Input: nums = [1, 3, 2, 2, 3, 1]
Output: One possible answer is [2, 3, 1, 3, 1, 2].
Note:
You may assume all input has valid answer.

My code:

class Solution(object):
    def wiggleSort(self, nums):
        """
        :type nums: List[int]
        :rtype: None Do not return anything, modify nums in-place instead.
        """
        nums.sort()
        tmp=nums[:]
        n=len(nums)
        left = (n - 1) / 2
        right = n - 1
        for i in range(len(nums)):
            if i % 2 == 0:
                nums[i] = tmp[left]
                left -= 1
            else:
                nums[i] = tmp[right]
                right -= 1
        

Solution: https://leetcode.com/problems/wiggle-sort-ii/